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Arithmetic type - Implicit conversions

An expression of type double is being implicitly converted to type unsigned char. A conversion of this kind may result in a loss of precision as the fractional element of the value is discarded. If the integral element of the value cannot be represented in type unsigned char, either because it is too large or because it is negative, the result will be meaningless.

For example: 


/*PRQA S 2017,3199,3203,3408,3447,3602 ++*/

extern double dbx;
extern void ef(unsigned char p);

extern void foo(void)
{
    unsigned char uca;

    uca = dbx;                  /* Message 3812 */

    ef(dbx);                    /* Message 3812 */
}

No MISRA C:2012 Rules applicable to message 3812

See also:

QA·C Source Code Analyser 8.1
MISRA C:2012 Compliance Module 1.0
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