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Arithmetic type - Implicit conversions

An expression of type signed short is being implicitly converted to type char. Is this intended ? This operation could result in data loss.

Implicit type conversions of this nature can occur in the context of:

In the C language there exist 3 distinct char types:

It is recommended that signed char and unsigned char should be used for "numeric" data and plain char should be used for "character" data. Numeric data can be stored in type char but the range of values will be implementation-defined because the type is sometimes implemented as a signed type and sometimes as an unsigned type. Likewise, character data can be stored in type signed char or type unsigned char, but it is more sensible to use type char.

For example:


/*PRQA S 2017,3197,3199,3203,3227,3408,3447,3602,3625 ++*/


extern void ef(char p);

extern char foo(signed short v)
{
    char a = v;                 /* Message 3733 */

    a = v;                      /* Message 3733 */

    ef(v);                      /* Message 3733 */

    return v;                   /* Message 3933 */
}


No MISRA-C:2004 Rules applicable to message 3933


See also:

QA·C Source Code Analyser 8.1
MISRA-C:2004 Compliance Module 3.2
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