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Arithmetic type - Implicit conversions

An expression of type long double is being implicitly converted to type unsigned char. A conversion of this kind may result in a loss of precision as the fractional element of the value is discarded. If the integral element of the value cannot be represented in type unsigned char, either because it is too large or because it is negative, the result will be meaningless.

For example: 


/*PRQA S 2017,3199,3203,3408,3447,3602 ++*/

extern long double ldx;
extern void ef(unsigned char p);

extern void foo(void)
{
    unsigned char uca;

    uca = ldx;                  /* Message 3823 */

    ef(ldx);                    /* Message 3823 */
}

No MISRA-C:2004 Rules applicable to message 3823

See also:

QA·C Source Code Analyser 8.1
MISRA-C:2004 Compliance Module 3.2
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