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Arithmetic type - Implicit conversions

An expression of integral type (unsigned short) is being implicitly converted to a floating type (double). Is this intended ?

Implicit type conversions of this nature can occur in the context of:


/*PRQA S 2017,3197,3199,3203,3227,3408,3447,3602,3625 ++*/

extern void ef(double f);

extern double foo(unsigned short n)
{
    double f = n;               /* Message 3753 - Initialization */

    f = n;                      /* Message 3753 - Assignment */

    f = f + n;                  /* Message 3753 - Balancing */

    ef(n);                      /* Message 3753 - Function argument */

    return n;                   /* Message 3953 - Function return */
}

See also:

QA·C Source Code Analyser 8.1.2
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