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Arithmetic type - Implicit conversions

An expression of type long double is being implicitly converted to type signed char. A conversion of this kind may result in a loss of precision as the fractional element of the value is discarded. If the integral element of the value cannot be represented in type signed char, the result will be meaningless.

For example: 


/*PRQA S 2017,3199,3203,3408,3447,3602 ++*/

extern long double ldx;
extern void ef(signed char p);

extern void foo(void)
{
    signed char sca;

    sca = ldx;                  /* Message 3822 */

    ef(ldx);                    /* Message 3822 */
}

See also:

QA·C Source Code Analyser 8.1.2
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