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Arithmetic type - Implicit conversions

An expression of type double is being implicitly converted to type unsigned int. A conversion of this kind may result in a loss of precision as the fractional element of the value is discarded. If the integral element of the value cannot be represented in type unsigned int, either because it is too large or because it is negative, the result will be meaningless.

For example: 


/*PRQA S 2017,3199,3203,3408,3447,3602 ++*/

extern double dbx;
extern void ef(unsigned int p);

extern void foo(void)
{
    unsigned int uia;

    uia = dbx;                  /* Message 3816 */

    ef(dbx);                    /* Message 3816 */
}

See also:

QA·C Source Code Analyser 8.1.2
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