QA·C Help - 0682

	0682	[C] Initializer for object of a character type is a string literal.

Constraint violations		REFERENCE - ISO:C90-6.5.7 Initialization - Semantics, ISO:C90-6.3.16.1 Simple Assignment - Constraints

This is a constraint error

An object of type 'char', 'signed char', 'unsigned char' or 'wchar_t' is being initialized with a string literal. A string literal has type 'array of char' and can only be used to initialise an object of compatible pointer type or array type. An object of type 'char' can only be initialised with an integral constant expression, for example a character constant.

For example:


/*PRQA S 753,2017,2211,3122,3132,3205,3408,3604,3625 ++*/

extern void foo(void)
{
    char h1     = "Y";         /* Message 0682 */
    char h2     = "hello\n";   /* Message 0682 */
    char buf[2] = "Y";         /* OK           */
    char *pc    = "hello\n";   /* OK           */
}

See also:

0683 [C] Initializer for object of a character type is a wide string literal.
0698 [C] String literal used to initialize an object of incompatible type.

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