[previous] 0258 [next] [S] String literal is not terminated. A backslash character has been used to define an escape sequence.
Syntax errors REFERENCE - ISO:C90-6.1.4 String Literals - Syntax

A string literal must begin and end on the same logical line. It appears that the terminating '"' character may not be recognised because it is preceded by a backslash character '\' and has become part of an escape sequence.

To represent a backslash character within a string literal, use the sequence '\\'. For example: 


/*PRQA S 753,2017,3122,3211,3408,3625 ++*/

    char *pca = "This literal ends with a backslash character \\";
    char *pcb = "This literal is not terminated \";                 /* Message 0258 */

QA·C Source Code Analyser 8.1.2
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